Two stations A and B are at a distance of 120 kilometers. Train X started from A towards B at a speed of 60 KMPH and after 30
minutes, Train Y started from B away from A at a speed of 30 KMPH. When will the two trains meet if we assume the departure of X
at A is the starting time and the halting time at station B is 10 minutes?
Answers
Answer:
Train x = 60 km/h
Train y = 30km /h
Train x begins first at 60 km/h.
In 1/2 hrs the distance covered by train x is :
1/2 × 60 = 30km
Let the total distance be D.
The distance remaining is (D - 30)km
Let the relative distance = 30km
Relative speed = 60 + 30 = 90 km/h
Time taken for them to meet is :
30/90 = 1/3 hrs
They meet after 1/3 hrs.
The total distance between a and b is :
(60 × 1/3 + 30) + (30 × 1/3)
(20 + 30) + 10 = 60 km
Step-by-step explanation:
Train A and B meet in 1.5 hr after train A starts.
Step-by-step explanation:
Given:
Two stations A and B are at a distance of 120 kilometers.
Train X started from A towards B at a speed of .
After 30 minutes, train Y started from B away from A at a speed of .
To Find:
The two trains meet after 100 min.
Solution:
As given,train X started from A towards B at a speed of .
Speed of train A = .
As given,After 30 minutes, train Y started from B away from A at a speed of .
Speed of train B = .
The train B starts after time
Let Train A and B meet in p hours after train A starts.
Distance covered by A in p hours = 60 p km.
Distance covered by B in ) hours
As given, two stations A and B are at a distance of 120 kilometers.
Distance between Stations A and B = 120 kilometers.
Thus,train A and B meet in 1.5 hr after train A starts.
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