Question

Two stones A and B are dropped from the top of two
different towers such that they travel 44.1 m and 63.7
m in the last second of their motion, respectively.
Find the ratio of the heights of the two towers from
where the stones were dropped.

Answer=25:49

Please give the solution ✌✌✌✌✌✌✌✌✌✌✌✌✌✌✌
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Answer 1

Let H = height of first tower , h = height of second tower

Distance travelled in last second

S = 44.1 m (For A) ; s = 63.7m (For B)

For stone A, 44.1 = 9.8/2 (2n - 1) ➝ (2n-1) = 9

For stone B, 63.7 = 9.8/2 (2n' - 1) ➝ (2n'-1) = 13

Clearly, n = 5 sec, and, n' = 7 sec.

[Note : n and n' are the time of descent for stone A and B respectively]

For the height of the tower from where stone A is dropped, H = 1/2 × g × 5²

For the height of the tower from where stone B is dropped, h = 1/2 × g × 7²

So, Ratio of their heights = 5² : 7² = 25:49

Answer 2

Answer:

$5 {}^2 .7 {}^{2} = 25.49$