Two stones are thrown towards each other simultaneously, one vertically downwards from the top of the
tower of height 360 m with velocity 10 m/s and other from the ground vertically upwards with velocity
50 m/s. Find the time and the distance from the ground at which they collide. [Take, g = 10 m/s^2]
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Answer:
time=6seconds
distance from ground is=120m
Explanation:
let distance from the ground at which they meet=X
for object thrown downwards
initial velocity=10m/s
acceleration=10m/s sq
distance at which they meet from upwards=360-x
time = T
use= s is equal to u t + half a t square
and find value of x
do same with second one and you will get your ans
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