Physics, asked by khushboomaharana06, 5 months ago

Two stones are thrown towards each other simultaneously, one vertically downwards from the top of the
tower of height 360 m with velocity 10 m/s and other from the ground vertically upwards with velocity
50 m/s. Find the time and the distance from the ground at which they collide. [Take, g = 10 m/s^2]​

Answers

Answered by DeevanshiMalik
2

Answer:

time=6seconds

distance from ground is=120m

Explanation:

let distance from the ground at which they meet=X

for object thrown downwards

initial velocity=10m/s

acceleration=10m/s sq

distance at which they meet from upwards=360-x

time = T

use= s is equal to u t + half a t square

and find value of x

do same with second one and you will get your ans

Similar questions