Question

Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of u2/1:u2/2

Answer 1

the intial velocity of one of the stone is u1
on the other hand, the intial velocity of second stone is u2.
lets prove that the height which mean the displacement covered by the stones are in ratio u2/1:u2/2.
let the ratio displacement of first stone will be u2/1x
"""""""""""""""""" second"""""""""""" u2/2x
now, u2/1x =u1/t
where time should be in sec
therefore , 1min=60sec.
u2/1x=u1/60
since u2/2x=ux
now, u2/1/u=2=>u1and u2

hence, proved






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Answer 2

Answer:

Explanation:

the intial velocity of one of the stone is u1

on the other hand, the intial velocity of second stone is u2.

lets prove that the height which mean the displacement covered by the stones are in ratio u2/1:u2/2.

let the ratio displacement of first stone will be u2/1x

"""""""""""""""""" second"""""""""""" u2/2x

now, u2/1x =u1/t

where time should be in sec

therefore , 1min=60sec.

u2/1x=u1/60

since u2/2x=ux

now, u2/1/u=2=>u1and u2

hence, proved