Question

Two stones having masses in the ratio of 3:2are dropped from the height in the ratio of 4:9 the ratio of magnitude of their linear momenta just before reaching the ground is

Answer 1

Ratio of masses = M/m = 3:2

Ratio of height= H/h = 4:9

u = 0m/s v = ?

g=10m/s

For finding the velocity of the stones with H;

2(4*10)+0=v²

√80=v

v=4√5

velocity with h height;

2(9*10)+0=v²

√180=v

v=6√5

Ratio of linear momentum of the 2 stones;

P/p = MV/mv=1:1

Therefore, the ratio of the linear momentum of the two stones is 1:1