Physics, asked by komalyadavvvv, 8 months ago

Two stones of masses m and 2 m are whirled in
r
horizontal circles, the heavier one in a radius
2
and lighter one in radius r. The tangential speed of
lighter stone is n times that of the value of heavier
stone when they experience same centripetal
forces. The value of n is
[Re-AIPMT-2015]
(1) 1
(2) 2
(3) 3
(4) 4​

Answers

Answered by sharansuryas2s
5

Given:

Two stones of masses m and 2m are whirled in

horizontal circles, the heavier one in a radius

2r and lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces.

Answer:

(1). 1

Explanation:

Given, their centripetal forces are the same.

m1(v1)^2/r1 = m2(v2)^2/r2

Here m1 = m, m2 = 2m, r1 = r, r2 = 2r, v1 = nv2

m(nv2)^2/r = 2m(v2)^2/2r

n^2(m(v2)^2)/r = m(v2)^2/r

n^2 = 1

n = 1

If the given value I provided is different, then just substitute the values in appropriate positions

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