Two Strips of metal are riveted together at their end by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 10⁷ Pa? Assume that each rivet is to carry one quarter of the load.
Answers
Answered by
2
solution:-
Given,
Diameter of the strip =6.0mm = 6.0×10^-3m
r = d/2
r= 6.0×10^-3= 3×10^-3m
maximum shearing stress =6.9 ×10^7 Pascale
maximum stress = minimum force / area
maximum force = maximum stress × area
= 6.9 ×10^7 ×π×r^2
= 6.9 × 10^6×π× (3×10^-3)^2
= 1949.94 N.
maximum force on each rivet = 4×1949.94 N
=> 7799.76 N
================
@GauravSaxena01
Given,
Diameter of the strip =6.0mm = 6.0×10^-3m
r = d/2
r= 6.0×10^-3= 3×10^-3m
maximum shearing stress =6.9 ×10^7 Pascale
maximum stress = minimum force / area
maximum force = maximum stress × area
= 6.9 ×10^7 ×π×r^2
= 6.9 × 10^6×π× (3×10^-3)^2
= 1949.94 N.
maximum force on each rivet = 4×1949.94 N
=> 7799.76 N
================
@GauravSaxena01
Answered by
0
Explanation:
Two Strips of metal are riveted together at their end by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 10⁷ Pa? Assume that each rivet is to carry one quarter of the load.
Similar questions