Question

Two students, appared at an examination One of them prures 9 mesmoreta tertentis
56% of the sum of their marks The marks obtained by them are​

Answer 1

Answer:

Let the students be A and B and the marks obtained by them be Am and Bm.

Am = Bm+9 …(1)

Am = (56/100)(Am+Bm), or

100Am = 56(Am+Bm) = 56Am + 56Bm, or

100Am-56Am = 44Am = 56Bm or

Am = (56/44)Bm = (14/11)Bm …(2)

Equate (1) and (2)

Bm+9 = (14/11)Bm, or

11(Bm+9) = 14Bm, or

11Bm+99 = 14Bm, or

!4Bm-11Bm = 3Bm = 99, or

Bm = 99/3 = 33.

So Am = 33+9 = 42.

A scored 42 marks while B scored 33. Answer.

Check. From (2), Am = (14/11)Bm = (14*33)/11 = (14*3) = 42. Correct