Question

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

Answer 1

The marks obtained by them are 42 and 33.

Step-by-step solution:-

Let their marks be  x and (x + 9)

Now, x + 9 = 56/100 (x + 9 + x)

=>25(x + 9) = 14(2x + 9)

=> 3x = 99

=> x = 33

=> x+9 = 33+9 = 42

Answer 2

Let their marks be (x + 9) and x.

Then, x + 9 =  56 /100(x + 9 + x)

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.