Question

Two students apperared for an examination one of them secured 24 marks more than the other and his marks were 65% of the sum of their marks the marks obtain by then are

Answer 1

Answer:

Let the marks scored by A be x and B be y .(x>y)

x-y =24

x=24+y

x =65/100 (x+y) ......(Given that value of x is 65%of their sum)

Substitution method,

24 + y = 65/100 (24+y+y)

24+y=15.6 + 1.3y

-0.3 y =15.6-24

0.3 y = 8.4

y=28

x=52

Marks scored by B is 28 and A is 52

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