Physics, asked by smily8545, 9 months ago

two students simultaneously start from the same place on a circular track and run for 2min. in this time one of them completes three and other 4 revolutions .due to thick vegetation in a circular area either of the boys can see only one third of track at a time .how long during their run do they visible to each other?

ans is 40sec pls explain it u get 50 points wrong ans will be reported

Answers

Answered by ItzIshu

$<!DOCTYPE html><html><head><title>CSS Heart Animation</title><style>.back{position:fixed;margin:auto;width:100%;heart:100%;top:0;bottom:0;left:0;right:0;padding:0;background-color:white;animation-name:back;animation-duration:3s;animation-iteration-count:infinite;}.heart{background-color:pink;margin:50% auto;top:0;bottom:0;right:0;left:0;padding:0;height:50px;width:50px;transform:rotate(-45deg);animation-name:heart;animation-duration:3s;animation-timing-function:ease-out;animation-iteration-count:infinite;}.heart:before,.heart:after{background-color:pink;position:absolute;content:"";width:50px;height:50px;border-radius:50%;}.heart:before{left:25px;}.heart:after{left:0;top:-25px;}@keyframes heart{0%{transform:scale(1)rotate(-45deg);}50%{transform:scale(0.6)rotate(-45deg);}}@keyframes back{0%{background-color:white;opacity:1;}50%{background-color:#ff0099;}}</style></head><body><div class="back"></div><div class="heart"></div></body></html>$

Answered by MohanNagaVijay

Answer:

40 seconds is the answer

Explanation:

Distance Traveled by A = 3c

velocity of A = 3c/2(60) (m/sec)

Distance Traveled by B = 4c

velocity of B = 4c/2(60) (m/sec)

Time for which they are Visible = T

T = distance they are Visible/Relative Velocity during Motion

T = (C/3)/(4c/120) - (3c/120)

T = 40 seconds

Previous Question

Next Question