Question

two supplementary and differ by 56°. find the angles

Answer 1

Let one of the angle be x°

Another angle=(x+56)°

x+x+56=180

2x=180-56

x=124/2

x=62

One angle=x=62°

Another angle=x+56=62+56=118°

Answer 2

Let one angle be x and other be (180-x)

➡ x - ( 180-x ) = 56

➡ x - 180+x = 56

➡ 2x = 56+180

➡ 2x = 236

➡ x = 118

Answer :-

two angles are -

x = 118

(180-x) = 180-118 = 62