two supplementary angle are in the ratio 7:11. find the angle
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Answered by
76
let angle be 7x and 11x
7x+11x = 180
18x = 180
x = 10
Angles are 7x = 7*10 = 70
11x = 11*10 = 110
7x+11x = 180
18x = 180
x = 10
Angles are 7x = 7*10 = 70
11x = 11*10 = 110
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Answered by
58
Let x be common multiple in ratio of angles.
Now, ratio is 7x : 11x
Sum of supplementary angles = 180°.
7x + 11x = 180°
18x = 180°
x = 10°
Now angles are 7x = 70°.
11x = 110°.
Thank you.
Now, ratio is 7x : 11x
Sum of supplementary angles = 180°.
7x + 11x = 180°
18x = 180°
x = 10°
Now angles are 7x = 70°.
11x = 110°.
Thank you.
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