Question

Two supplementary angle differ by 34°,
find the angles.​

Answer 1

Answer:

Answer:Let the smaller angle be x

Answer:Let the smaller angle be x

Answer:Let the smaller angle be x Since the two angles differ by 34

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180 We have x+(x+34)=180

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180 We have x+(x+34)=180 2x+34=180

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180 We have x+(x+34)=180 2x+34=180 2x=180−34=146

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180 We have x+(x+34)=180 2x+34=180 2x=180−34=146

Answer:Let the smaller angle be x Since the two angles differ by 34 , the bigger angle =x+34 Since the sum of the supplementary angles is 180 We have x+(x+34)=180 2x+34=180 2x=180−34=146 x= 146/2=73

=73 Therefore smaller angle =x=73

Bigger angle =x+34=73+34=107

Answer 2

Answer:

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Let the small angle be x°

Since the two angles differ by 34°

,the bigger angle = x + 34°

Since the sum of the supplementary angles is 180°

We have ,

$x + (x + 34) = 180° \\ 2x + 34 = 180° \\ 2x = 180 - 34 = 146° \\ x = \frac{146°}{2} = 73°. \\ therefore \: smaller \: angle = x = 73° \\ bigger \: angle \: = x + 34 = 73 + 34 = 107°$

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