Question

two supplementary angle differ by 56 degree. find the angles​

Answer 1

Answer:

Let one angle be x

Let another be x+56

(Or could solve by x-56)

ATQ

x+x+56=180

2x=124

x=62°

One angle is x=62°

Second angle is x+56°=62+56=118°

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Answer 2

Explanation:

Let X , (180°- X) are two supplementary angle

According to problems given

X+ (180°-x) = 56°

x-180°+ X= 56°

2x= 56°+180°

2x = 236°

X=236°/2

×=118°

therefore

first angle X =118°

second angle 180°- X = 180-118= 62°

hope it helps you