two supplementary angles are in the ratio 11:7 find the angles.plz help me it's emergency...
Answers
Answered by
0
Hey!
Let one angle be 11x°.
Let the other angle be 7x°.
According to your problem, they are supplementary angles.
Hence,
11x+7x=180
=>18x=180
=>x=10
The first angle = (10×11) = 110°.
The second angle = (10×7) = 70°.
Hope this helps you!
Let one angle be 11x°.
Let the other angle be 7x°.
According to your problem, they are supplementary angles.
Hence,
11x+7x=180
=>18x=180
=>x=10
The first angle = (10×11) = 110°.
The second angle = (10×7) = 70°.
Hope this helps you!
mahaakal:
hi
Answered by
0
solution
here,
Let the two angle be 11x and 7x
According to the question,
11 x +7x = 180
or, 18x = 180
or , x= 180/ 18
or , x=10
And,
the 1st angle =11x (putting the value of x)
=11 × 10
= 110
the 2nd angle = 7x
= 7 × 10
=70
Therefore , the angles are 110 and 70 degree.
here,
Let the two angle be 11x and 7x
According to the question,
11 x +7x = 180
or, 18x = 180
or , x= 180/ 18
or , x=10
And,
the 1st angle =11x (putting the value of x)
=11 × 10
= 110
the 2nd angle = 7x
= 7 × 10
=70
Therefore , the angles are 110 and 70 degree.
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