two supplementary angles are in the ratio 11:7.find the angles.
Answers
Answered by
6
Hey!
Let one angle be 11x°.
Let the other angle be 7x°.
According to your problem, they are supplementary angles.
Hence,
11x+7x=180
=>18x=180
=>x=10
The first angle = (10×11) = 110°.
The second angle = (10×7) = 70°.
Hope this helps you!
Let one angle be 11x°.
Let the other angle be 7x°.
According to your problem, they are supplementary angles.
Hence,
11x+7x=180
=>18x=180
=>x=10
The first angle = (10×11) = 110°.
The second angle = (10×7) = 70°.
Hope this helps you!
Answered by
3
let the angles be 11x and 7x
so,
By question,
11 x + 7x = 180
18x = 180
x = 10
and
1st angle = 11 x ( putting the value of x)
= 11 × 10
=110
2 nd angle =7x
= 7 × 10
= 70
therefore, the angles are 110 and 70 degrees.
so,
By question,
11 x + 7x = 180
18x = 180
x = 10
and
1st angle = 11 x ( putting the value of x)
= 11 × 10
=110
2 nd angle =7x
= 7 × 10
= 70
therefore, the angles are 110 and 70 degrees.
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