Question

two supplementary angles are in the ratio 11:7.find the angles.

Answer 1

let the ratio term be x
then the ratio becomes 11x and 7x
then A/Q
11x + 7x = 180
18x = 180
so, X = 180/18 = 10
therefore the first angle be 11x = 11*10 = 110
and the second angle be 7x = 7*10 = 70

Answer 2

Let the angle be x

1st angle = 11x

2nd angle = 7x

Sum of supplementary angles is 180°

ATQ,

11x + 7x = 180°

18x = 180°

x = $\frac{180}{18}$

x = 10°


1st angle is 11x = 11 × x = 11 × 10 = 110°

2nd angle = 7x = 7 × x = 7 × 10 = 70°