two supplementary angles are in the ratio 3:2, find the angles
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Sum of supplementary angles = 180°
Let us the given ratio be 3x:2x.
So,
ATQ,
3x + 2x = 180°.
or 5x = 180°.
or x = 180°/5.
Therefore x = 36°.
Therefore 1st angle = 2x = 2×36°=72°.
Therefore 2nd angle = 3x = 3×36°= 108°.
Answered by
2
let the angles be x
so, 3x,2x .
now ,
supplementary angles =180
3x+2x=180
5x=180
x=180/5
x=36
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