Two supplementary angles differ by 34.find the angles
Answers
Answered by
71
let the two numbers be x and X+34
x+x+34=180°
2x+34=180°
2x=180°-34
2x=146°
x=146°/2
x=73°
x=73°
x+34=107°
x+x+34=180°
2x+34=180°
2x=180°-34
2x=146°
x=146°/2
x=73°
x=73°
x+34=107°
hitesh0:
thanks
Answered by
16
HEYA MATE, HERE IS UR ANSWER
Other angle=(180-x)
According to the question
180-x-(x)=34
180-x-x=34
180-2x=34
-2x=34-180
-2x=-146
x=
x=73
So one angle=73 degrees
Another angle=180-73
=107 degrees
Other angle=(180-x)
According to the question
180-x-(x)=34
180-x-x=34
180-2x=34
-2x=34-180
-2x=-146
x=
x=73
So one angle=73 degrees
Another angle=180-73
=107 degrees
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