Two supplementary angles differ by 44 degree .Find the angles
Answers
Answered by
23
Let one angle be x
Then another angle will be x-44.
We know that sum of supplementary angle is 180°
x + (x-44) = 180°
x + x = 180 + 44
2x = 224
x = 224/2
x = 112°
So angle are,
x = 112° &
x -44 = 112 - 44
= 68
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Then another angle will be x-44.
We know that sum of supplementary angle is 180°
x + (x-44) = 180°
x + x = 180 + 44
2x = 224
x = 224/2
x = 112°
So angle are,
x = 112° &
x -44 = 112 - 44
= 68
Hope it helps.
Plz mark it brainliest.
Answered by
9
Hi friend, Harish here.
Here is you answer:
Let, One angle be x.
Then the other angle = 180 - x ( Because sum of supplementary angles is 180).
Given that,
Difference of the angles = 44°.
Then , ( 180 - x - x ) = 44°
⇒ ( 180 -2x) = 44°
⇒ 180 - 44 = 2x
⇒ 2x = 136.
⇒ x = 136 ÷ 2
⇒ x = 68°
Therefore the angles are: i) x = 68° & ii) 180 - x = 180 - 68 = 112°
__________________________________________________
Hope my answer is helpful to you.
Here is you answer:
Let, One angle be x.
Then the other angle = 180 - x ( Because sum of supplementary angles is 180).
Given that,
Difference of the angles = 44°.
Then , ( 180 - x - x ) = 44°
⇒ ( 180 -2x) = 44°
⇒ 180 - 44 = 2x
⇒ 2x = 136.
⇒ x = 136 ÷ 2
⇒ x = 68°
Therefore the angles are: i) x = 68° & ii) 180 - x = 180 - 68 = 112°
__________________________________________________
Hope my answer is helpful to you.
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