Two supplementary angles differ by 48.
differ then the angles are
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let the first angle =X
second angle =180-X
Now,
180-X-X=48
180—2X=48
=—2X=-132
— — cancel
2X=132
X=66
First angle=66
Second angle =180-66=114
Hence, the angles are 114 and 66 who differ by 48
second angle =180-X
Now,
180-X-X=48
180—2X=48
=—2X=-132
— — cancel
2X=132
X=66
First angle=66
Second angle =180-66=114
Hence, the angles are 114 and 66 who differ by 48
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