Two supplementryangles differs by 40 degree. Then larger is
Answers
let first angle= x degrees
let second angle be= x+40 degrees ( as is given in the question)
we know that both angles are supplementary. so, their sum
according to the question:-
x+x+40=180
2x=180-40
2x=140
x=140/2
x=70 degrees
therefore, angle 1= 70 degrees
and angle 2 = 70+40= 110 degrees
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Answer:
Step-by-step explanation:
Since,
The sum of two supplimentary angles = 180 degrees
Given that
Difference of the two supplimentary angles = 40
Let, 1st supplimentary angle = x
and
So, 2nd Supplimentary angles = x + 40
a/q
Sum of the two supplimentary angles = x + (x + 40)
=2x + 40 = 180
= 2x = 180 - 40 = 140
= x = 140/2 = 70 degrees
1st angle = x = 70 degrees
2nd angle = x+40 = 70+40 = 110 degrees
So, the larger angle = 110 degree
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