Two swimmers begin a race and Swimmer A completes each length of the pool in 30 seconds, while Swimmer B completes each length in 40 seconds. How faar ahead of Swimmer B will Swimmer A be after 5 minutes?
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Answer:
Step-by-step explanation:
Here we need to convert the minutes to seconds .
The conversion is follows :
1 minute = 60 seconds.
We have 5 minutes.
The total number of seconds is as follows:
= 60 × 5 = 300 seconds.
Swimmer A:
300/30 = 10
Swimmer A will have gone 10 times the length of the pool.
Swimmer B:
300/40 = 7.5
In 5 minutes Swimmer B will have gone 7.5 times.
Swimmer A will be (10 - 7.5) far ahead of B.
= 10 - 7.5 = 2.5
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