Question

Two swimmers begin a race and Swimmer A completes each length of the pool in 30 seconds, while Swimmer B completes each length in 40 seconds. How faar ahead of Swimmer B will Swimmer A be after 5 minutes?

Answer 1

Answer:

Step-by-step explanation:

Here we need to convert the minutes to seconds .

The conversion is follows :

1 minute = 60 seconds.

We have 5 minutes.

The total number of seconds is as follows:

= 60 × 5 = 300 seconds.

Swimmer A:

300/30 = 10

Swimmer A will have gone 10 times the length of the pool.

Swimmer B:

300/40 = 7.5

In 5 minutes Swimmer B will have gone 7.5 times.

Swimmer A will be (10 - 7.5) far ahead of B.

= 10 - 7.5 = 2.5