two syringes of different cross section ( without needle) filled with water are connected with a tightly fitted rubber tube . diameters of the smaller and larger piston are 1.0cm and 3.0 cm respectively. if the smaller piston is pushed in through 6.0cm. how much does the larger piston move out ?
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Hey dear,
● Answer -
Movement of larger piston = 0.667 cm
● Explaination -
Area of small piston -
A1 = πr1^2
A1 = π × 1^2
A1 = π cm^2
Area of large piston -
A2 = πr2^2
A2 = π × 3^2
A2 = 9π cm^2
Length by which large piston moves is calculated by -
L1A1 = L2A2
L2 = L1A1 / A2
L2 = 6 × 1 / 9
L2 = 0.667 cm
Therefore, larger piston will move through 0.667 cm.
Hope this helps you...
● Answer -
Movement of larger piston = 0.667 cm
● Explaination -
Area of small piston -
A1 = πr1^2
A1 = π × 1^2
A1 = π cm^2
Area of large piston -
A2 = πr2^2
A2 = π × 3^2
A2 = 9π cm^2
Length by which large piston moves is calculated by -
L1A1 = L2A2
L2 = L1A1 / A2
L2 = 6 × 1 / 9
L2 = 0.667 cm
Therefore, larger piston will move through 0.667 cm.
Hope this helps you...
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