Two syringines of different cross sections filled with water are connected with a tightly fitted rubber tube filled with water.diameters of smaller piston and larger piston are 1cm and 3cm.find the force exerted on larger piston when a force 10N is applied to a smaller piston
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F1(force on smaller piston)
F2(force on larger piston)
A1(area of smaller piston)
A2(area of larger piston)
F2=A2/A1*F1
=pai{3/2*10(power -2)m}(power 2)/pai{1/2*10(power-2)m}(power2)*10N
=90N
HOPE IT HELPS!!!!!!
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