Two tables and three chairs cost 3.500, and three tables and two chairs cost
4,000. What is the cost of a table and that of a chair?
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Answer:
So allowing tables=t, and chairs=c, then:
2t+3c=3500
3t+2c=4000
2t+3t+2c+3c=7500
(5t+5c)÷5=7500÷5
t+c=1500
t=1500-c
2(1500-c)+3c=3500
3000–3000–2c+3c=3500-3000
c=500
3t+2(500)=4000
3t+1000–1000=4000–1000
3t÷3=3000÷3
t=1000
3 tables and 2 chairs is 4000
3×1000=3000
2×500=1000
3000+1000=4000
2 tables and 3 chairs is 3500
2×1000=2000
3×500=1500
2000+1500=3500
So the cost of one table is 1000.
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