The foot of a ladder is 6 m away from a wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its tip reach?
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Given : The foot of a ladder is away from a wall : 6 m
Its foot is away from the wall = 8 m
Let, length of ladder be AD = BE = l m
In ∆ACD, by Pythagoras theorem
AD² = AC² + CD²
AD² = 8² + 6²
AD² = 64 + 36
AD² = 100
AD =√100
AD = 10 m
AD = BE = l =10 m.
In ∆BCE, by Pythagoras theorem
BE² = BC² + CE²
10² = BC² + 8²
100 = BC² + 64
BC² = 100 - 64
BC² = 36
BC = √36
BC = 6 m
Hence,its tip reach the height of 6 m.
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