Question

Two tags are chosen probability of drawing 2 consecutive numbers

Answer 1

Solution:

Let events

E - first tag is an end tag (1 or n)

I - first tag is not an end tag (interior tags)

C - second tag is consecutive to the first (either way)

For the first tag,

P(E)=$\frac{2}{N}$ (tags 1 and n out of n tags)

P(I) = $\frac{n-2}{n}$ (the non-end tags, or interior tags)

Can you please mark my answer as the BRAINLIEST it will help me a lot