Two tailors A n B earn rs 300 and 400 per day resp. A can stitch 6 shirts and 4 pairs of trousers while B can stitch 10 shirts and 4 pairs of trousers per day. To find how many days should each of them work and if it is desired to produce at least 60 shirts and 32 pairs of trousers at a minimum labour cost. , Formulate this as an lpp
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Hey !!
Shirts Trousers Payment per day
(x) A 6 4 Rupees 300
(x) B 10 4 Rupees 400
------- -------
60 32
Let A work for x and B for y days
Constraints : z = 300 x + 400 y
4x + 4y ≥ 32
x ≥ 0
y ≥ 0
PQR is the solution
P (3,3) z = 300 (s) + 400 (s) = Rupees 2700
Q (0,8) z = 400 (8) = Rupees 3200
R (10,0) z = 300 (10) = Rupees 3000
Hence, z is minimum when A works for 5 days and B works for 3 days.
GOOD LUCK !!
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