two tangents making an angle of 120 degrees are drawn to a circle of radius 6cm. What is the length of each tangent
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Given
Radius of the circle = 6cm
∠PAQ = 120°
Construction
Join AO
Solution
Since, the tangents are perpendicular to radius through the point of contact
∠OPA = 90° ----> (1)
∠OQA = 90° ----> (2)
In ∆OAP and ∆OAQ
AO = AO (Common)
AP = AQ (Length of the tangents to the same external point is equal)
∠OPA = ∠OQA {From (1) and (2)}
∴ ∆OAP ≡ ∆OAQ (by SAS Congreuency rule)
By CPCT, ∠OAP = ∠OAQ ----> (3)
∠OAP + ∠OAQ = ∠PAQ
=> ∠OAP + ∠OAP = 120° {From (3)}
=> 2 ∠OAP = 120°
=> ∠OAP = 120°/2 = 60°
Now, In ∆OAP, ∠P = 90°
Tan A = OP/AP
=> Tan 60° = 6/AP
=> √3 = 6/AP
=> AP = 6/√3
=> AP = 2√3 cm
∴ the length of each tangent = 2√3 cm
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