Question

Two tangents PA and PB are drawn from an external point P to a circle with centre O . Prove that AOBP is a cyclic quadrilateral​

Answer 1

Answer:

Hey guys

Step-by-step explanation:

Since, OA⊥AP and OB⊥BP

∠PAO+∠PBO=90

o

+90

o

=180

o

⟹∠APB+∠AOB=180

o

⟹AOBP is a cyclic quadrilateral.

solution

Please mark my brianlist