two tankers contain 180litre and 240litre of petrol respectively find the maximum capacity of container which can measure the petrol of either tanker in esect no of times
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Answered by
4
The capacity of required container will be obtained by finding the HCF of the capacity of tankers -
180 = 2×2x5×3×3
240 = 2×2×2×2x2x5
Common factors of 180 and 240=2x2x5
HCF = 2x2x5
= 20
Answer) The container which can measure petrol of either tank exactly must be of 20 litres.
180 = 2×2x5×3×3
240 = 2×2×2×2x2x5
Common factors of 180 and 240=2x2x5
HCF = 2x2x5
= 20
Answer) The container which can measure petrol of either tank exactly must be of 20 litres.
Anonymous:
I am sorry 240=2x2x2x2x3x5
240 factor are wrong
what is the ans
i think 20
srry 30 l
tell me
yes you right
because HCF=2x3x5=30
sorry for wrong answer
no problem
Answered by
1
capacity of first tanker= 180 litre
capacity of second tanker= 240 litre
maximum capacity of container which can measure petrol
=HCF(180,240)
180= 2*2*5*3*3
240=2*2*2*3*2*5
HCF=2*5*3
=30
capacity of second tanker= 240 litre
maximum capacity of container which can measure petrol
=HCF(180,240)
180= 2*2*5*3*3
240=2*2*2*3*2*5
HCF=2*5*3
=30
is that right
ya
hmm
hey give me anss of my next question
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