Question

Two tankers contains 825 litres and 675 litres of kerosene oil respectively.Find the maximum capacity of a container which can measure the kerosene oil of both the tankers when an exact number of times

Answer 1

The maximum capacity of a container which can measure the kerosene oil of both the tankers when an exact number of times is 75 L.

Concept used:

For finding the maximum capacity of a container we have to find the HCF of the given numbers.

We have use Euclid's division lemma to find the HCF.

Euclid's division lemma :

a = bq + r

Here, a = Dividend, b = divisor, q = quotient and r = remainder

Dividend = (Divisor × quotient) + Remainder

Given:

Capacities of two tankers of kerosene oil are 825 L and 675 L.

To find:

The maximum capacity of a container which can measure the kerosene oil of both the tankers when an exact number of times.

Solution:

Step 1: Using Euclid's division lemma in 825 L and 675 L:

Here, 825 > 675

Now, 825 = (675 x 1) + 150

Here, remainder = 175 ≠ 0.

So, new dividend is 675 and divisor is 150.

Step 2: Using Euclid's division lemma in 675 L and 150 L.

Now, 675 = (150 x 4) + 75

Here, remainder = 75 ≠ 0.

So, new dividend is 150 and divisor is 75.

Step 3: Using Euclid's division lemma in 150 L and 75 L.

Now, 150 = (75 x 2) + 0

Here, remainder is zero and divisor is 75.

So, the HCF of 825 and 675 is 75.

Hence, the maximum capacity of the required container is 75 L.

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