two tanks contain water at 40 degrees centigrade and 90 degrees centigrade respectively.the amount of water to be taken from each tank to make 40 kg water at 50 degrees centigrade is.....
Answers
Answered by
2
mixture of waters at two different temperatures.
T1 = 40°C T2 = 90°C
M1 = ? M2 = ?
Mixture: M = M1 + M2 = 40 kg T = 50°C
T = (M1 * T1 + M2 * T2 ) / (M1 + M2)
= [ M1 * T1 + (M - M1) * T2 ] / M
50 = [ M1 * 40 + (40 - M1) * 90 ] / 40
2000 = 3600 - 50 M1
M1 = 32 Kg
M2 = 40 - 32 = 8 kg
T1 = 40°C T2 = 90°C
M1 = ? M2 = ?
Mixture: M = M1 + M2 = 40 kg T = 50°C
T = (M1 * T1 + M2 * T2 ) / (M1 + M2)
= [ M1 * T1 + (M - M1) * T2 ] / M
50 = [ M1 * 40 + (40 - M1) * 90 ] / 40
2000 = 3600 - 50 M1
M1 = 32 Kg
M2 = 40 - 32 = 8 kg
Similar questions