Two tanks, i and ii have capacities in ratio 3:4 respectively. A pipe fills tank i in 5 hrs at constant rate. How many hours will it take for the same pipe to fill tank ii if the rate at which the pipe fills the tank is doubled
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Answer:
both pipe fill tanks in 30 minutes
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Step-by-step explanation:
Let the capacities be 3x and 4x respectively.
By using the formula,
R × T = V
R1 × 5 = 3x i.e R1 = 3x/5
2R1 × t = 4x i.e R1 = 2x/t
(Since same pipe is used to fill the pipes, R will be same)
Now compare the values of R1,
3x/5 = 2x/t
Therefore, t = 10/3
i.e t = 3 1/3
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