two taps A and B can fill a cistern in 20 and 30 minutes. both the pipe being open. find when the 1st pipe must be turned off so that the cistern may be filled in 10 minutes more.
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Answer:
8 minutes
Step-by-step explanation:
% Cistern is filled by 1st pipe in one minute = 10020
= 5%
% Cistern is filled by 2nd pipe in one minute = 10030
= 3.33%
% cistern filled by 1st and 2nd pipes in one minute = 8.33%
According to question,
Cistern is totally filled by 2nd pipe in last 10 minute.
That means 2nd pipe filled 33.3% of the cistern in last 10 minute and 66.66% of cistern is filled by 1st and 2nd pipe together in = 66.668.33
= 8 minutes
Thus, after 8 minute, 1st pipe must be turned off.
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