Two taps a and b can fill a tank in 12 minutes and 15 minutes respectively. If both the taps are opened simultaneously and the tap a is closed after 3 minutes, then how much more time will it take to fill the tank by tap b?
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Let the total capacity of the tank be 60 units. (a multiple of 12 and 15)
So the efficiency of tap A = 60/12 = 5 units/min
efficiency of tap B = 60/15 = 4 units/min
Initially both taps are opened, so they will fill 5+4= 9 units in 1 min.
In 3 minutes they will fill 27 units.
Remaining tank to be filled is 60-27 = 33 units
Now as per the question only tap B operates which will take 33/4 = 8.25 minutes.
So the efficiency of tap A = 60/12 = 5 units/min
efficiency of tap B = 60/15 = 4 units/min
Initially both taps are opened, so they will fill 5+4= 9 units in 1 min.
In 3 minutes they will fill 27 units.
Remaining tank to be filled is 60-27 = 33 units
Now as per the question only tap B operates which will take 33/4 = 8.25 minutes.
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