Two taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank?
Answers
Answer:
36
Step-by-step explanation:
Given Two taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank?
- In 1 hour, part filled by pipe A will be 1/5
- In 1 hour, part filled by pipe B will be 1/20
- So in 1 hour, A and B will fill the tank in 1/5 + 1/20 = 1/4
- Now A and B together can fill the tank in 4 hours
- It is given due to leakage it took 30 min more to fill the tank.
- So the tank was filled in 4 30/60 hours = 4 ½ hours = 9/2.
- Now total filled and leakage by pipe A and B will be 2/9 hours.
- Again part emptied due to leakage in 1 hour will be
1/4 – 2/9
= 9 – 8 / 36
= 1/36
So the leakage can empty the tank in 36 hours.
Answer:
leakage can empty tank in 36 Hrs alone
Step-by-step explanation:
Two taps A and B can fill a tank in 5 hours and 20 hours respectively.
Tap A fills in 1 hr = 1/5
Tap B fills in 1 hr = 1/20
Tap A & B together fill in 1hr = 1/5 + 1/20 = (4 + 1)/20 = 1/4
Tap A & B together fill tank in = 1/(1/4) = 4 Hr
Let say leakage can empty tank alone in = L hrs
Leakage in 1 hr = 1/L
Tap A + Tap B + Leakage in 1 hr = 1/4 - 1/L
Tap A + Tap B + Leakage fill tank in = 4 hr + 30 minutes = 9/2 hrs
Tap A + Tap B + Leakage fill tank in 1 hr = 2/9
1/4 - 1/L = 2/9
=> 9 - 36/L = 8
=> 1 = 36/L
=> L = 36
leakage can empty tank in 36 Hrs alone