Two taps A and B can together fill a swimming pool in 15 days. The taps A and B are kept open for 12 days and then the tap B is closed. It took another 8 days for tap A to fill the pool. How many days does each tap require to fill the pool?
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According to question
1/A + 1/B = 1/15 Eqn 1
Also
A + B = 12
Taking LCM in Eqn 1 and putting the value
A + B/ AB = 1/15
AB/ A+B = 15
AB = 15 *12
AB = 180
Also
1/A+8 = 1/B
Thus
B = A + 8
So
B^2- 8B-180 = 0
B(B-18) +10 (B-18) = 0
Thus B= 18
and A = 6
1/A + 1/B = 1/15 Eqn 1
Also
A + B = 12
Taking LCM in Eqn 1 and putting the value
A + B/ AB = 1/15
AB/ A+B = 15
AB = 15 *12
AB = 180
Also
1/A+8 = 1/B
Thus
B = A + 8
So
B^2- 8B-180 = 0
B(B-18) +10 (B-18) = 0
Thus B= 18
and A = 6
sam404:
What is B^2??
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