Question

Two taps A and B can togetherr fll a Swimming pool in 15 days. Taps A and B are kept open for 12 days and then tap B is closed. It takes another 8 days for the pool to be filled. How many days does each tap require to fill the pool? ​

Answer 1

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Let A and B be the rate of two taps

According to the question

15A+15B=1 job--------(i)

20A+12B=1 job---------(ii)

Multiply (i) by 12 and (ii) by 15

180A+180B=12-----------(iii)

300A+180B=15----------(iv)

Subtract (iii) from (iv) we get

120A=3

A=1/40 job/day

A would take 40 days to fill the pool alone

20A+12B=1

1/2+12B=1

12B=1/2

B=1/24 job/day

B would take 24 days to fill the pool alone