Two taps a and b fill a tank separately in 24 minutes and 40 minutes respectively and a waste pipe c releases 30 litres per minute. If all the pipes are opened the tank is filled in an hour. The capacity of the tank is
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Work Efficiency of Pipe One = 100/24 = 4.16% per minute
Work Efficiency of Pipe two = 100/40 = 2.5% %per minute.
Work Efficiency of third pipe which is doing a negative work = 30 gallons per minute
All three pipes can fill empty tank in 60 minute.
Work efficiency together = 100/60 = 1.66% per minute
Work Efficiency of third pipe = (1.66 - (4.16 +2.5)) = - 5
So, 5 = 30 gallons
1% = 30/5
Thus, 100% = (30*100)/5
So, Capacity of the tank = 600 gallons.
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