Question

two taps can fill the tank in 20 min and 30min third tap can empty the tank in 1/15 min


​

Answer 1

Answer:

it was a wrong question you must check this

Answer 2

Answer:

Tap B

Step-by-step explanation:

Part of the tank filled by the taps A, B and C in 3 min.

= 120+130−115=3+2−460=160

Therefore, Time taken to fill [1−(12+130)] or

5560th part of the tank = 3×55 = 165 min.

Remaining part of the tank = 1−5560=560=112

Tap A fills 120 part in 1 min,

Then, Remaining part = 112−1220=5−360=260=130

i.e., 130th part is filled by B in 1 min.