Question

Two thermometer x and y have ice points marked at 15°and 25°and steam point marked as 75°and125°.when thermometer x measure the temperature of a bath as 60°on it what would thermometer y read when it is used to measure the of the same bath

Answer 1

Answer:100C

Explanation:60-15/75=y-25/125

Solve for y and you will get y=100C

Pls mark branliest!!!

Answer 2

Thermometer y would read 100°C when it is used to measure the of the same bath.

For thermometer X,

Given the temperature of bath = 60°C

and, the ice point marked on 15°C

Again, steam point marked on 75°C

So, for X,

(Temp.of bath-Ice point)/(Steam point - Ice point) = constant

⇒(60°C - 15°C)/( 75°C - 15°C) = constant

⇒constant = 3/4

For thermometer X,

Let the temperature of bath = Y°C

and, the ice point marked on 25°C

Again, steam point marked on 125°C

So, for Y,

(Temp.of bath-Ice point)/(Steam point - Ice point) = constant

⇒(Y°C - 25°C)/( 125°C - 25°C) = 3/4

⇒(Y°C - 25°C) = (3/4)×100 = 75

⇒ Y = 75°C + 25°C = 100°C

This is the required temperature.