Two thin lenses f1 = 10 cm and f2 = 20 cm are separated by a distance d = cm. Their optical centre
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Two thin lenses f1 = 10 cm and f2 = 20 cm are separated by a distance d = cm. Their optical centre
Ans. Power of lens: It is the reciprocal of focal length of a lens.
P = 1/f (f is in metre)
Unit of power of lens: Diopter.
An object is placed at point O. The lens A produces an image at I1which serves as a virtual object for lens B which produces final image at I.
Given, the lenses are thin. The optical centres (P) of the lenses A and B is co-incident.
For lens A, we have
If two lenses are considered as equivalent to a single lens of focal length f, then
1/v - 1/u = 1/f ....(iv)
From equation (iii) and equation (iv), we can write
1/f = 1/f1 + 1/f2
SO MARK AS BRAINIEST PLEASE.
Ans. Power of lens: It is the reciprocal of focal length of a lens.
P = 1/f (f is in metre)
Unit of power of lens: Diopter.
An object is placed at point O. The lens A produces an image at I1which serves as a virtual object for lens B which produces final image at I.
Given, the lenses are thin. The optical centres (P) of the lenses A and B is co-incident.
For lens A, we have
If two lenses are considered as equivalent to a single lens of focal length f, then
1/v - 1/u = 1/f ....(iv)
From equation (iii) and equation (iv), we can write
1/f = 1/f1 + 1/f2
SO MARK AS BRAINIEST PLEASE.
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