Two thin wood screens A and B are separated by 200m . A bullet travelling horizontally at a speed of 600m/s hits the screen A ,penetrates through it finally emerges out from B making holes in A and B . If the resistance of air and wood are negligible , the difference of heights of the holes in A and B
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Secondary SchoolPhysics 5+3 pts
Two thin wood screens A and B are separated by 200m . A bullet travelling horizontally at a speed of 600m/s hits the screen A ,penetrates through it finally emerges out from B making holes in A and B . If the resistance of air and wood are negligible , the difference of heights of the holes in A and B is
Report by Subbukolchina 30.07.2017
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Kunchekarthik2003 · Helping Hand
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sivaprasad2000
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Here the bullet should be considered as a projectile
Initially the bullet had 600 m/s horizontal velocity, the gravitational force creates an acceleration vertically downwards, it will not alter the horizontal velocity.
So the time taken by the bullet to cover a horizontal displacement 200m will be equal to
time = 200/600 = 1/3 seconds
Mean while the vertical motion of the bullet is accelerated
vertical displacement of the bullet = h = ut+(1/2)a(t^2)
u = 0 m/s
a = g = 9.8 m/s
t = 1/3 s
h = 0.5 x 9.8 x (1/9) = 0.544 m (Ans)
(Correction in picture v = 600 m/s)