two Towers height 28m 36m respectively are built at a distance of 15m find the distance between the their tops.
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Let ab is the first and ce is the second tower.
Ab = 28m
Ce= 36m
Ad = bc = 15m
De = ce - Cd
DE = 36 - 28
De = 8m
Join a to e.
Now by using bodhayam theorm. ⤵️⤵️
==>Ae^2= (ad)^2+ (de)^2
==>(ae)^2 = 225 + 64
==>(ae)^2 = 289
==>Ae = 17m
Ab = 28m
Ce= 36m
Ad = bc = 15m
De = ce - Cd
DE = 36 - 28
De = 8m
Join a to e.
Now by using bodhayam theorm. ⤵️⤵️
==>Ae^2= (ad)^2+ (de)^2
==>(ae)^2 = 225 + 64
==>(ae)^2 = 289
==>Ae = 17m
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