Question

two towers of height 28mand 36m are built at distance of 15 M find the distance between the tops of the towers

Answer 1

Here's the answer


Refer the attachment.

Here,


Height of the tower FB = 36 m
Height of the tower DC = 28 m
Distance between the towers = AD = 15 m

Therefore,
BC = 15 m

Let the distance between the top of the two towers ( FD ) be x metre.

In right angled triangle FAD,

$\sf{FD^2 = AF^2 + AD^2 }$

$\sf{x {}^{2} = 8 {}^{2} + 15 {}^{2}}$

$\sf{x {}^{2} = 64 + 225}$

$\sf{x {}^{2} = 289}$

$\sf{x = \sqrt{289} }$

$\sf{x = 17 \: m}$

Therefore,

Distance between the top of the towers is 17 metre.

Thanks!

Answer 2

Suppose the distance between height of the towers be p

The height diffeence of towers :-

36 - 28 = 8m  (a)

The distance between two towers is 15m  (b)

Pythogaras theorem

a² + b² = p²

8² + 15² = p²

64 + 225 = p²

289 = p²

17 = p

Distance between towers = 17 m