Question

two towers of height 39 M and 30 M stand upright at a distance of 12 m from each other find the distance between their tops

Answer 1

BC=12 m
AB=30m
CE=39m
DE =9m
AD=12m


${h}^{2} = p {}^{2} + b {}^{2}$
$ae {}^{2} = de { }^{2} + ad {}^{2} \\ ae {}^{2} = 9 {}^{2} + 12 {}^{2} \\ ae {}^{2} = 81 + 144 \\ ae {} = \sqrt{225} \\ ae = 15m$