Question

two towns A and B are 400 km apart Prakash and Jagdish started their cars from towns A and B respectively at the same time towards each other . When they were 10kilometers apart,the speed of prakash car exceeded the the speed of Jagdish car by 10km/hr , find their respective speeds.

Answer 1

Answer:

Let speed of car starting from A=x km/hr and speed of car starting from B=y km/hr.

Relative speed of A with respect to B when moving in same direction =x−y km/hr.

Relative speed of A with respect to B when moving in opposite direction =x+y km/hr.

Distance between A and B=100 km.

We know, Time=SpeedDistance

From the above information, we have,

x−y100=5andx+y100=1

or,x−y100=5=>100=5(x−y)=>20=x−y=>x=y+20....(i)Also,x+y100=1=>100=x+y=>x+y=100....(ii)

By substitution method,

Substituting equation (i) in equation (ii), we get,

x+y=100=>y+20+y=100=>2y=80=>y=40

Substituting y=40 in equation (i), we get,

x=y+